x^2-160x+6000=0

Solution for x^2-160x+6000=0 equation:

x^2-160x+6000=0

a = 1; b = -160; c = +6000;
Δ = b2-4ac
Δ = -1602-4·1·6000
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-40}{2*1}=\frac{120}{2}
=60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+40}{2*1}=\frac{200}{2}
=100
$